(1/3)v^2+27=12

Solution for (1/3)v^2+27=12 equation:

(1/3)v^2+27=12

We move all terms to the left:

(1/3)v^2+27-(12)=0


Domain of the equation: 3)v^2!=0

v!=0/1

v!=0

v∈R


We add all the numbers together, and all the variables

(+1/3)v^2+27-12=0

We add all the numbers together, and all the variables

(+1/3)v^2+15=0

We multiply all the terms by the denominator


(+1+15*3)v^2=0

We add all the numbers together, and all the variables

46v^2=0

a = 46; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·46·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$v=\frac{-b}{2a}=\frac{0}{92}=0$